The gas OF₂ can be produced from the electrolysis of an aqueous solution of KF,as shown in the equation below:
OF₂(g) + 2 H⁺(aq) + 4 e^- → H₂O(l) + 2 F^-(aq) E° = +2.15 V
Using the given standard reduction potential,calculate the amount of OF₂ that is produced,and the electrode at which the OF₂ is produced,upon the passage of 0.480 faradays through an aqueous KF solution.

Question

Quizplus · Accepted Answer

The given equation shows that OF₂ is produced at the anode. The amount of OF₂ produced can be calculated using the formula:mass = (current × time × molar mass) / (number of electrons × Faraday's constant)Substituting the given values, we get:mass = (0.480 F × 1 s × 54.00 g/mol) / (2 mol e^- × 96,485 C/mol) = 6.48 gTherefore, the correct answer is A) 6.48 g of OF₂ at the anode.

The Gas OF2 Can Be Produced from the Electrolysis of an Aqueous

The Gas OF₂ Can Be Produced from the Electrolysis of an Aqueous