The aquation of tris (1,10-phenanthroline) iron(II) in acid solution takes place according to the equation:
Fe(phen) ₃²⁺ + 3 H₃O⁺ + 3 H₂O → Fe(H₂O) ₆²⁺ + 3 phenH⁺.
If the activation energy,E_a,is 126 kJ mol^-1 and the rate constant at 30 °C is 9.8 × 10^-3 min^-1,what is the rate constant at 35 °C?

Question

Quizplus · Accepted Answer

We can use the Arrhenius equation to solve this problem:

k = A * exp(-Ea/RT)

where:
- k is the rate constant
- A is the pre-exponential factor
- Ea is the activation energy
- R is the gas constant (8.314 J/mol K)
- T is the temperature in Kelvin

We can rearrange the equation to solve for k at a different temperature:

k2 = A * exp(-Ea/R * (1/T2 - 1/T1))

where:
- k2 is the rate constant at the new temperature (35 °C or 308 K)
- T2 is the new temperature in Kelvin (308 K)
- T1 is the original temperature in Kelvin (303 K)

We can plug in the given values and solve for k2:

k2 = (9.8 × 10^-3 min^-1) * exp(-126000 J/mol / (8.314 J/mol K * (1/308 K - 1/303 K)))

k2 = 2.2 × 10^-3 min^-1

Therefore, the best choice is B.

The Aquation of Tris (1,10-Phenanthroline)iron(II)in Acid Solution Takes Place According