In seawater,Mg²⁺ is about 1350 mg Mg²⁺/L.How many grams of magnesium are in a pool that is 25 ft by 12 ft by 6 ft? (1 ft = 12 inches and 1 inch = 2.54 cm)

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First, convert the pool dimensions from feet to centimeters to calculate the volume in liters, since 1 cubic centimeter (cm³) is equivalent to 1 milliliter (mL), and there are 1000 mL in a liter. The pool dimensions are 25 ft x 12 ft x 6 ft. Using the conversion factors, 1 ft = 12 inches and 1 inch = 2.54 cm, the dimensions in centimeters are (25 ft * 12 in/ft * 2.54 cm/in) x (12 ft * 12 in/ft * 2.54 cm/in) x (6 ft * 12 in/ft * 2.54 cm/in). This gives a volume in cubic centimeters, which is directly convertible to liters. Given that seawater contains approximately 1350 mg of magnesium per liter, you can then calculate the total mass of magnesium in the pool by multiplying the volume of the pool in liters by the concentration of magnesium in mg/L, and then converting mg to grams by dividing by 1000 mg/g. The correct calculation leads to an answer in the order of magnitude of 10^14 grams, which corresponds to choice C, 6.88 × 10^14 g.

In Seawater,Mg2+ Is About 1350 Mg Mg2+/L

In Seawater,Mg²⁺ Is About 1350 Mg Mg²⁺/L