At 273 K,ΔG° for the reaction 2 C(s)+ O₂(g)→ 2 CO(g) Is about -280 kJ,and at 1480 K is about -580 kJ. For the reaction 2 Zn(s)+ O₂(g)→ 2 ZnO(s) ΔG° at 273 K and 1480 K,respectively,is -640 and -280 kJ.Calculate ΔG° at 273 K and 1480 K,respectively,for the reduction of zinc oxide by carbon. A)+180 and -150 kJ B)+360 and -300 kJ C)-360 and +300 kJ D)-180 and +150 kJ

Question

Quizplus · Accepted Answer

The reduction of zinc oxide by carbon can be represented as:2 ZnO(s) + 2 C(s) → 2 Zn(s) + 2 CO(g)To find ΔG° for this reaction, we use the given ΔG° values for the reactions:1. 2 C(s) + O2(g) → 2 CO(g)2. 2 Zn(s) + O2(g) → 2 ZnO(s)At 273 K:ΔG° = ΔG°(2 C + O2 → 2 CO) - ΔG°(2 Zn + O2 → 2 ZnO)= (-280 kJ) - (-640 kJ) = +360 kJAt 1480 K:ΔG° = ΔG°(2 C + O2 → 2 CO) - ΔG°(2 Zn + O2 → 2 ZnO)= (-580 kJ) - (-280 kJ) = -300 kJTherefore, the correct choice is A: +180 and -150 kJ.

At 273 K,ΔG° for the Reaction