In the cation [CrCl₂(H₂O)₄]⁺,the oxidation state of chromium and its coordination number,respectively,are ________. A)-3 and two B)+3 and six C)0 and four D)+2 and six E)-4 and six

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The given cation is [Cr(H2O)4Cl2]+. In this complex, Cr is bonded to four H2O molecules and two Cl atoms. The oxidation state of Cr can be calculated by considering the charges of the ligands (H2O is neutral and Cl is -1) and the overall charge of the complex (+1). Let the oxidation state of Cr be x. Thus, 4(0) + 2(-1) + x = +1, solving for x gives x = +3. The coordination number, which is the number of atoms directly bonded to the central metal atom, is six (four from H2O and two from Cl).

In the Cation [CrCl2(H2O)4]+,the Oxidation State of Chromium and Its

In the Cation [CrCl₂(H₂O)₄]⁺,the Oxidation State of Chromium and Its