In the Hardy-Weinberg equation,p² + 2pq + q² = 1.If the dominant allele frequency is 0.8,what percent of the population will be homozygous dominant?

Question

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In the Hardy-Weinberg equation, p^2 represents the frequency of the homozygous dominant genotype. Given that the dominant allele frequency (p) is 0.8, the frequency of the homozygous dominant genotype is p^2 = (0.8)^2 = 0.64 or 64%.

In the Hardy-Weinberg Equation,p2 + 2pq + Q2 = 1

In the Hardy-Weinberg Equation,p² + 2pq + Q² = 1