If you conduct a monohybrid cross of two heterozygous Yy pea plants,what percentage of the offspring will be heterozygous?

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In a monohybrid cross between two heterozygous Yy pea plants, the genotypes of the parents are Yy and Yy. When we make a Punnett square to determine the possible genotypes of their offspring, we see that there are four possible outcomes: YY, Yy, Yy, and yy. Out of these four possible genotypes, two are heterozygous (Yy). Therefore, the percentage of offspring that will be heterozygous is 2 out of 4, or 50%.

If You Conduct a Monohybrid Cross of Two Heterozygous Yy