Given the following information about a hypothesis test of the difference between two means based on independent random samples,what is the calculated value of the test statistic? Assume that the samples are obtained from normally distributed populations having equal variances.
H_A: ?_A > ?_B, $\bar { X }$
₁ = 12, $\bar { X }$
₂ = 9,s₁ = 5,s₂ = 3,n₁ = 13,n₂ = 10.

Question

Given the following information about a hypothesis test of the difference between two means based on independent random samples,what is the calculated value of the test statistic? Assume that the samples are obtained from normally distributed populations having equal variances.
H_A: ?_A > ?_B,

\bar { X }

₁ = 12,

\bar { X }

₂ = 9,s₁ = 5,s₂ = 3,n₁ = 13,n₂ = 10.

Quizplus · Accepted Answer

The calculated value of the test statistic is t = 1.674. This can be calculated using the formula:t = ($\bar { X }$₁ - $\bar { X }$₂) / sqrt((s₁^2/n₁) + (s₂^2/n₂))Plugging in the given values, we get:t = (12 - 9) / sqrt((5^2/13) + (3^2/10)) = 1.674

Given the Following Information About a Hypothesis Test of the Difference