There are an average of 22.455 employees at 22 office furniture dealers in a province with a standard deviation of 18.52.If the number of employees can be approximated by a normal distribution,the 99% confidence interval for the true mean number of full-time employees at office furniture dealers would be _____.
A)[11.014,33.896]
B)[11.277,33.633]
C)[12.284,32.626]
D)[12.513,32.397]
E)[20.072,24.838]

Question

Quizplus · Accepted Answer

The 99% confidence interval is calculated using the formula: mean ± (Z * (standard deviation/√n)). For a 99% confidence level, Z is approximately 2.576. Plugging in the values: 22.455 ± (2.576 * (18.52/√22)) gives the interval [11.277, 33.633].

There Are an Average of 22