Find an individual 95 percent confidence interval for
$\mu _ { 1 } - \mu _ { 2 }$
where $\bar { x } _ { 1 }$
= 33.98, $\bar { x } _ { 2 }$
= 36.56,and MSE = 0.669.There were 15 observations in total and 3 treatments.Assume that the number of observations in each treatment is equal.

Question

Find an individual 95 percent confidence interval for
$\mu _ { 1 } - \mu _ { 2 }$ 
where $\bar { x } _ { 1 }$ 
= 33.98, $\bar { x } _ { 2 }$ 
= 36.56,and MSE = 0.669.There were 15 observations in total and 3 treatments.Assume that the number of observations in each treatment is equal.

Quizplus · Accepted Answer

The Answer of Find an individual 95 percent confidence interval for
$\mu _ { 1 } - \mu _ { 2 }$ 
where $\bar { x } _ { 1 }$ 
= 33.98, $\bar { x } _ { 2 }$ 
= 36.56,and MSE = 0.669.There were 15 observations in total and 3 treatments.Assume that the number of observations in each treatment is equal.

Find an Individual 95 Percent Confidence Interval For μ1−μ2\mu _ { 1 } - \mu _ { 2 }μ1​−μ2​

Find an Individual 95 Percent Confidence Interval For $\mu _ { 1 } - \mu _ { 2 }$