Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 groups (treatments). $\begin{array} { l c } \text { Source } & \text { Sum of Squares } \\\text { Treatments } & 15.93 \\\text { Blocks } & 42.09 \\\text { Error } & 23.84 \\\text { Total } & 81.86\end{array}$
-Test H₀: there is no difference between treatment effects at a =.05.

Question

Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 groups (treatments).

\begin{array} { l c } \text { Source } & \text { Sum of Squares } \\\text { Treatments } & 15.93 \\\text { Blocks } & 42.09 \\\text { Error } & 23.84 \\\text { Total } & 81.86\end{array}

-Test H₀: there is no difference between treatment effects at a =.05.

Quizplus · Accepted Answer

The Answer of Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 groups (treatments). $$\begin{array} { l c } \text { Source } & \text { Sum of Squares } \ \text { Treatments } & 15.93 \ \text { Blocks } & 42.09 \ \text { Error } & 23.84 \ \text { Total } & 81.86 \end{array}$$ -Test H₀: there is no difference between treatment effects at a =.05.

Consider the Following Partial Analysis of Variance Table from a Randomized