The heat of vaporization of water is 540 cal/g. What mass of water at 100.0 °C can be vaporized by the addition of 55.0 kcal of heat?
A)0.19 g
B)55 g
C) g
D)102 g

Question

The heat of vaporization of water is 540 cal/g. What mass of water at 100.0 °C can be vaporized by the addition of 55.0 kcal of heat?
A)0.19 g 
B)55 g 
C) g 
D)102 g

Quizplus · Accepted Answer

Use the formula:

q = m * L

where q is the amount of heat absorbed, m is the mass of the substance, and L is the heat of vaporization.

Rearranging the formula to solve for the mass:

m = q / L

Substituting the values given:

m = (55.0 kcal) / (540 cal/g) = 0.102 g

Therefore, the mass of water that can be vaporized is 0.102 g, which is approximately 102 g.

Thus, the correct answer is D.

The Heat of Vaporization of Water Is 540 Cal/g