Consider the following reaction.
NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)
If 25.0 mL of a 0.100 M solution of NaOH reacted with excess HCl, how many moles of NaCl could form?

Question

Consider the following reaction. NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l) If 25.0 mL of a 0.100 M solution of NaOH reacted with excess HCl, how many moles of NaCl could form?

Quizplus · Accepted Answer

The balanced equation shows that 1 mole of NaOH reacts with 1 mole of HCl to produce 1 mole of NaCl.

First, we need to find the number of moles of NaOH present in the given volume:

moles of NaOH = volume (in L) x concentration 
moles of NaOH = 0.025 L x 0.100 mol/L 
moles of NaOH = 0.0025 mol

Since NaOH and HCl react in a 1:1 ratio, the number of moles of NaCl that can form will also be 0.0025 mol. Therefore, the correct answer is (C) 0.00250 mol.

Consider the Following Reaction