A sample of a radioacitive isotope has an activity of 80 μCi when produced. 60 min later when it is being used the activity has dropped to 10 μCi. What is the half-life of this isotope?

Question

Quizplus · Accepted Answer

The half-life can be calculated using the formula for radioactive decay, which is $A = A_0 \times (1/2)^{t/T}$, where $A$ is the final activity, $A_0$ is the initial activity, $t$ is the time elapsed, and $T$ is the half-life. Plugging in the given values, $10 = 80 \times (1/2)^{60/T}$. Solving for $T$, we find that the half-life $T = 20$ minutes.

A Sample of a Radioacitive Isotope Has an Activity of 80