How many fluorine atoms are there in 65 g of CF₄?

Question

Quizplus · Accepted Answer

The molar mass of CF₃S₁UB₁₄ is approximately equal to 288 g/mol. 
The molar mass of fluorine is approximately equal to 19 g/mol. 
Therefore, there is approximately 288/19 = 15.2 moles of CF₃S₁UB₁₄ in 65 g of CF₃S₁UB₁₄.

Each mole of CF₃S₁UB₁₄ contains 3 fluorine atoms. 
Therefore, there are 15.2 x 3 = 45.6 fluorine atoms in 65 g of CF₃S₁UB₁₄, which can be rounded to 46.

Using scientific notation, 46 can be represented as 4.6 x 10¹, and rounded to 1 significant figure, the answer is 1.8 x 10²⁴. 
Therefore, the best choice is D, which represents this answer.

How Many Fluorine Atoms Are There in 65 G of CF4

How Many Fluorine Atoms Are There in 65 G of CF₄