When 50.0 mL of a 0.3000 M AgNO₃ solution is added to 50.0 mL of a solution of MgCl₂, an AgCl precipitate forms immediately.The precipitate is then filtered from the solution, dried, and weighed.If the recovered AgCl is found to have a mass of 0.1183 g, what as the concentration of magnesium ions in the original MgCl₂ solution? A)0.300 M B)8.25 × 10^-3 M C)1.65 × 10^-2 M D)2.06 × 10^-5 M E)4.13 × 10^-3 M

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Quizplus · Accepted Answer

The balanced chemical equation for the reaction is:2AgNO3(aq) + MgCl2(aq) → 2AgCl(s) + Mg(NO3)2(aq)From the stoichiometry of the balanced chemical equation, we can see that 2 moles of AgNO3 react with 1 mole of MgCl2. Therefore, the concentration of MgCl2 in the original solution can be calculated as follows:[MgCl2] = (0.3000 M AgNO3)(50.0 mL AgNO3 solution)/(2)(50.0 mL MgCl2 solution) = 0.01500 MTherefore, the concentration of magnesium ions in the original MgCl2 solution is 8.25 × 10-3 M.

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