For the Reaction C₆H₁₄(g) $\rarr$ C₆H₆(g)+ 4H₂(g) $\Delta$ P(H₂) $\Delta$ T Was Found to Be 2

For the reaction C₆H₁₄(g) $\rarr$ C₆H₆(g) + 4H₂(g) , $\Delta$ P(H₂) / $\Delta$ t was found to be 2.5 × 10^-2 atm/s, where $\Delta$ P(H₂) is the change in pressure of hydrogen.Determine $\Delta$ P(C₆H₁₄) / $\Delta$ t for this reaction at the same time.

A) 2.5 × 10^-2 atm/s
B) -6.2 × 10^-3 atm/s
C) -2.5 × 10^-2 atm/s
D) 0.10 atm/s
E) 6.2 × 10^-3 atm/s