Predict the direction in which the equilibrium will lie for the reaction C₆H₅COO^- + HF
C₆H₅COOH + F^-.
K_a(C₆H₅COOH) = 6.5 × 10^-5; K_a(HF) = 7.1 × 10^-4

Question

Predict the direction in which the equilibrium will lie for the reaction C₆H₅COO^- + HF

Predict the direction in which the equilibrium will lie for the reaction C<sub>6</sub>H<sub>5</sub>COO<sup>-</sup> + HF <sub> </sub> <sub> </sub>C<sub>6</sub>H<sub>5</sub>COOH + F<sup>- </sup>. K<sub>a</sub>(C<sub>6</sub>H<sub>5</sub>COOH) = 6.5 × 10<sup>-5</sup>; K<sub>a</sub>(HF) = 7.1 × 10<sup>-4</sup> A) to the right B) to the left C) in the middle

C₆H₅COOH + F^-.
K_a(C₆H₅COOH) = 6.5 × 10^-5; K_a(HF) = 7.1 × 10^-4

Quizplus · Accepted Answer

The equilibrium constant for the forward reaction is greater than the equilibrium constant for the reverse reaction. Therefore, the equilibrium will lie to the right, favoring the formation of products.

Predict the Direction in Which the Equilibrium Will Lie for the Reaction