The molar solubility of magnesium carbonate is 1.8 × 10^-4 mol/L.What is K_sp for this compound?

Question

Quizplus · Accepted Answer

The balanced chemical equation for the dissolving of magnesium carbonate is:

MgCO3(s) ⇌ Mg2+(aq) + CO32-(aq)

The solubility product constant expression for magnesium carbonate is:

Ksp = [Mg2+][CO32-]

If the molar solubility of MgCO3 is x, then [Mg2+] = x mol/L and [CO32-] = x mol/L. Therefore,

Ksp = x * x = x^2

Given the molar solubility of MgCO3 is 1.8 × 10^-4 mol/L, then

Ksp = (1.8 × 10^-4)^2 = 3.24 × 10^-8

Therefore, the answer is D) 3.2 × 10^-8.

The Molar Solubility of Magnesium Carbonate Is 1