To 1.00 L of a 0.100 M aqueous solution of benzoic acid (C₆H₅COOH)is added 1.00 mL of 12.0 M HCl.What is the percentage ionization of the benzoic acid in the resulting solution? [K_a(C₆H₅COOH)= 6.5 × 10^-5]

Question

Quizplus · Accepted Answer

The addition of a strong acid like HCl suppresses the ionization of benzoic acid due to the common ion effect. The concentration of H⁺ ions from HCl is much higher than from benzoic acid, reducing its ionization. Calculating the ionization using the given K_a and the new concentration of H⁺ gives approximately 0.52%.

To 100 L of a 0