Find the Concentration of Pb²⁺ Ions in a Solution Made

Find the concentration of Pb²⁺ ions in a solution made by adding 5.00 g of lead(II) iodide to 500.mL of 0.150 M KI.[For PbI₂, K_sp = 1.39 × 10^-8.]

A) 3.04 × 10^-4 M
B) 1.54 × 10^-7 M
C) 6.18 × 10^-7 M
D) 1.52 × 10^-4 M
E) 9.27 × 10^-8 M