The element oxygen was prepared by Joseph Priestley in 1774 by heating mercury(II) oxide: HgO(s) $\rarr$ Hg(l) + ¹/₂O₂(g) , $\Delta$ H° = 90.84 kJ/mol.
Estimate the temperature at which this reaction will become spontaneous under standard state conditions.
S°(Hg) = 76.02 J/K·mol
S°(O₂) = 205.0 J/K·mol
S°(HgO) = 70.29 J/K·mol

Question

The element oxygen was prepared by Joseph Priestley in 1774 by heating mercury(II) oxide: HgO(s)

\rarr

Hg(l) + ¹/₂O₂(g) ,

\Delta

H° = 90.84 kJ/mol.
Estimate the temperature at which this reaction will become spontaneous under standard state conditions.
S°(Hg) = 76.02 J/K·mol
S°(O₂) = 205.0 J/K·mol
S°(HgO) = 70.29 J/K·mol

Quizplus · Accepted Answer

The Answer of The element oxygen was prepared by Joseph Priestley in 1774 by heating mercury(II)oxide: HgO(s)$\rarr$Hg(l)+ ¹/₂O₂(g), $\Delta$H° = 90.84 kJ/mol. Estimate the temperature at which this reaction will become spontaneous under standard state conditions. S°(Hg)= 76.02 J/K·mol S°(O₂)= 205.0 J/K·mol S°(HgO)= 70.29 J/K·mol A)108 K B)430 K C)620 K D)775 K E)840 K

The Element Oxygen Was Prepared by Joseph Priestley in 1774 →\rarr→

The Element Oxygen Was Prepared by Joseph Priestley in 1774 $\rarr$