For the reaction SbCl₅(g) SbCl₃(g)+ Cl₂(g), $\Delta$G°_f (SbCl₅)= -334.34 kJ/mol $\Delta$G°_f (SbCl₃)= -301.25 kJ/mol $\Delta$H°_f (SbCl₅)= -394.34 kJ/mol $\Delta$H°_f (SbCl₃)= -313.80 kJ/mol Will this reaction proceed spontaneously at 298 K and 1 atm pressure?

Question

Quizplus · Accepted Answer

The Answer of For the reaction SbCl₅(g) SbCl₃(g)+ Cl₂(g), $\Delta$G°_f (SbCl₅)= -334.34 kJ/mol $\Delta$G°_f (SbCl₃)= -301.25 kJ/mol $\Delta$H°_f (SbCl₅)= -394.34 kJ/mol $\Delta$H°_f (SbCl₃)= -313.80 kJ/mol Will this reaction proceed spontaneously at 298 K and 1 atm pressure?

For the Reaction SbCl5(g) SbCl3(g)+ Cl2(g) Δ\DeltaΔ G°f (SbCl5)= -334

For the Reaction SbCl₅(g)
SbCl₃(g)+ Cl₂(g) $\Delta$ G°_f (SbCl₅)= -334