Calculate the standard enthalpy change for the reaction 2C8H18(l) + 21O2(g) 8CO(g) + 8CO2(g) + 18H2O(l) .
Given:
2C8H18(l) + 25O2(g) 16CO2(g) + 18H2O(l) H° = -11,020 kJ/mol
2CO(g) + O2(g) 2CO2(g) H° = -566.0 kJ/mol
A) 1.0454 * 104 kJ/mol
B) -8,756 kJ/mol
C) 1.1586 * 104 kJ/mol
D) -6,492 kJ/mol
E) -1.0454 * 104 kJ/mol
Correct Answer:
Verified
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