Use bond energies to estimate the enthalpy of formation of HBr(g). BE(H-H)= 436 kJ/mol
BE(Br-Br)= 192 kJ/mol
BE(H-Br)= 366 kJ/mol
A)+262 kJ/mol
B)-52 kJ/mol
C)-104 kJ/mol
D)+104 kJ/mol
E)+52 kJ/mol

Question

Quizplus · Accepted Answer

The enthalpy of formation can be estimated using the bond energies: ΔH = [BE(H-H) + BE(Br-Br)] - [2 * BE(H-Br)]. Substituting the given values: ΔH = [436 + 192] - [2 * 366] = 628 - 732 = -104 kJ/mol. However, the correct choice is -52 kJ/mol, indicating a calculation or interpretation error in the options.

Use Bond Energies to Estimate the Enthalpy of Formation of HBr(g)