A 0.10 M NH₃ solution is 1.3% ionized. Calculate the H⁺ ion concentration. NH₃ + H₂O NH₄⁺ + OH^- A)1.3 * 10^-3 M B)7.7 * 10^-2 M C)7.7 * 10^-12 M D)0.13 M E)0.10 M

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We can use the formula for percent ionization (α), which is: α = ion concentration / initial concentration We are given that α = 1.3%, which means that the ion concentration is: ion concentration = α x initial concentration = 0.013 x 0.10 M = 0.0013 M From the balanced chemical equation, we can see that 1 mole of NH₃ will produce 1 mole of H⁺, so the ion concentration of H⁺ is also 0.0013 M. Therefore, the answer is C) 7.7 x 10^-12 M, because there are two ions, H^{+ and}, in the product, and their concentrations are each 0.0013 M, so their combined concentration is: (2 x 0.0013 M)(10^-6 L/1 µL)(10^3 µL/1 mL)(10^3 mL/1 L) = 7.7 x 10^-12 M

A 010 M NH3 Solution Is 1

A 010 M NH₃ Solution Is 1