Rubidium has a heat of vaporization of 69.0 kJ/mol at its boiling point (686°C).Calculate $\Delta$S for this process, Rb(l)$\rarr$ Rb(g), at 1 atm and 686°C.

Name: Rubidium has a heat of vaporization of 69.0 kJ/mol at its boiling point (686°C).Calculate $\Delta$S for this process, Rb(l)$\rarr$ Rb(g), at 1 atm and 686°C.
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The Answer of Rubidium has a heat of vaporization of 69.0 kJ/mol at its boiling point (686°C).Calculate $\Delta$S for this process, Rb(l)$\rarr$ Rb(g), at 1 atm and 686°C.

Rubidium Has a Heat of Vaporization of 69 Δ\DeltaΔ S for This Process, Rb(l)

Rubidium Has a Heat of Vaporization of 69 $\Delta$ S for This Process, Rb(l)