Consider the reaction CO(g)+ 2H₂(g) CH₃OH(l)at 25°C. $\Delta$G°_f (CO)= -137.3 kJ/mol $\Delta$G°_f (CH₃OH)= -166.3 kJ/mol $\Delta$H°_f (CO)= -110.5 kJ/mol $\Delta$H°_f (CH₃OH)= -238.7 kJ/mol S°(CO)= 197.9 J/K·mol S°(CH₃OH)= 126.8 J/K·mol Calculate S°(H₂(g))_.

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The Answer of Consider the reaction CO(g)+ 2H₂(g) CH₃OH(l)at 25°C. $\Delta$G°_f (CO)= -137.3 kJ/mol $\Delta$G°_f (CH₃OH)= -166.3 kJ/mol $\Delta$H°_f (CO)= -110.5 kJ/mol $\Delta$H°_f (CH₃OH)= -238.7 kJ/mol S°(CO)= 197.9 J/K·mol S°(CH₃OH)= 126.8 J/K·mol Calculate S°(H₂(g))_.

Consider the Reaction CO(g)+ 2H2(g) CH3OH(l)at 25°C Δ\DeltaΔ G°f (CO)= -137

Consider the Reaction CO(g)+ 2H₂(g) CH₃OH(l)at 25°C $\Delta$ G°_f (CO)= -137