What would the concentration of OH^- be if the concentration of H₃O⁺ was 1 × 10^-8M? [H₃O⁺] × [OH^-] = K_w= 1 × 10^-14 A)1 × 10^-14 B)1 × 10^-6 C)1 × 10⁸ D)1 × 10⁶ E)1 × 10^-8

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Quizplus · Accepted Answer

Given the ion product of water (Kw) is 1 × 10^-14 M^2, and the concentration of H3O+ is 1 × 10^-8 M, the concentration of OH- can be found by dividing Kw by the concentration of H3O+. Therefore, [OH-] = 1 × 10^-14 M^2 / 1 × 10^-8 M = 1 × 10^-6 M.

What Would the Concentration of OH- Be If the Concentration

What Would the Concentration of OH^- Be If the Concentration