What would the concentration of H₃O⁺ be if the concentration of OH^- was 1 × 10^-11M? [H₃O⁺] × [OH^-] = K_w= 1 × 10^-14 A)1 × 10^-3 B)1 × 10³ C)1 × 10¹⁴ D)1 × 10¹² E)1 × 10^-6

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Given the ion product of water (Kw) is 1 × 10^-14, and the concentration of OH^- is 1 × 10^-11 M, the concentration of H3O+ can be found using the relation Kw = [H3O+][OH^-]. Substituting the given values, 1 × 10^-14 = [H3O+](1 × 10^-11), solving for [H3O+] gives 1 × 10^-3 M.

What Would the Concentration of H3O+ Be If the Concentration

What Would the Concentration of H₃O⁺ Be If the Concentration