An iron mine produces 1.67 × 10⁴ tons of raw ore per day. If the ore is 26.39% elemental iron, the mine produces ________ pounds of elemental iron per year. (Assume the mine operates 365 days per year.) A)1.221 × 10¹⁰ B)8.814 × 10⁶ C)3.217 × 10⁹ D)1.611 × 10⁶ E)3.66 × 10¹¹

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First, calculate the annual production of raw ore: 1.67 × 10^4 tons/day × 365 days/year = 6.0955 × 10^6 tons/year. Then, calculate the annual production of elemental iron: 6.0955 × 10^6 tons/year × 0.2639 = 1.608 × 10^6 tons/year. Convert tons to pounds (1 ton = 2000 pounds): 1.608 × 10^6 tons/year × 2000 pounds/ton = 3.216 × 10^9 pounds/year, which is approximately 3.217 × 10^9 pounds/year.

An Iron Mine Produces 1