Lead (II)carbonate decomposes to give lead (II)oxide and carbon dioxide: PbCO₃ (s)→ PbO (s)+ CO₂(g) How many grams of lead (II)oxide will be produced by the decomposition of 2.50 g of lead (II)carbonate? A)0.41 B)2.50 C)0.00936 D)2.09 E)2.61

Question

Quizplus · Accepted Answer

First, we need to balance the chemical equation, but it seems already balanced: PbCO3 (s) → PbO (s) + CO2 (g). Next, we calculate the molar mass of lead (II) carbonate (PbCO3) which is 207.2 (Pb) + 12.01 (C) + 3*16.00 (O3) = 267.21 g/mol. The molar mass of lead (II) oxide (PbO) is 207.2 (Pb) + 16.00 (O) = 223.2 g/mol. Given 2.50 g of PbCO3, we find the moles of PbCO3: 2.50 g / 267.21 g/mol = 0.00936 mol. Since the reaction is a 1:1 ratio, the moles of PbO produced will also be 0.00936 mol. To find the mass of PbO produced: 0.00936 mol * 223.2 g/mol = 2.09 g.

Lead (II)carbonate Decomposes to Give Lead (II)oxide and Carbon Dioxide