The combustion of ammonia in the presence of oxygen yields NO₂ and H₂O: 4 NH₃ (g) + 7 O₂ (g) → 4 NO₂ (g) + 6 H₂O (g)
The combustion of 43.9 g of ammonia with 258 g of oxygen produces ________ g of NO₂.

Question

Quizplus · Accepted Answer

The balanced equation shows that 4 moles of NH3 produce 4 moles of NO2. The molar mass of NH3 is 17.03 g/mol, so 43.9 g of NH3 is 2.58 moles. This will produce 2.58 moles of NO2. The molar mass of NO2 is 46.01 g/mol, so 2.58 moles of NO2 is 119 g.

The Combustion of Ammonia in the Presence of Oxygen Yields