The change in the internal energy of a system that releases 2,500 J of heat and that does 7,655 J of work on the surroundings is ________ J. A)-10,155 B)-5,155 C)-1.91 × 10⁷ D)10,155 E)5,155

Question

Quizplus · Accepted Answer

The change in internal energy ($\Delta U$) of a system can be calculated using the first law of thermodynamics, which is $\Delta U = Q - W$, where $Q$ is the heat added to the system and $W$ is the work done by the system on the surroundings. Here, $Q = -2500$ J (since heat is released by the system, it's considered negative) and $W = 7655$ J. Thus, $\Delta U = -2500 J - 7655 J = -10155$ J.

The Change in the Internal Energy of a System That