The specific heat capacity of lead is 0.13 J/g-K. How much heat (in J)is required to raise the temperature of 15 g of lead from 22 °C to 37 °C? A)2.0 J B)-0.13 J C)5.8 × 10^-4 J D)29 J E)0.13 J

Question

Quizplus · Accepted Answer

The formula for calculating the amount of heat (Q) required to raise the temperature of a substance is:

Q = m * c * ΔT

where:
m = mass of the substance
c = specific heat capacity of the substance
ΔT = change in temperature

Substituting the given values:
m = 15 g
c = 0.13 J/g-K
ΔT = (37-22) °C = 15 °C

Q = 15 g * 0.13 J/g-K * 15 °C
Q = 29 J

Therefore, the amount of heat required to raise the temperature of 15 g of lead from 22 °C to 37 °C is 29 J. Option D is the best choice.

The Specific Heat Capacity of Lead Is 0