Given the following reactions CaCO₃ (s)→ CaO (s)+ CO₂ (g)ΔH = 178.1 kJ C (s,graphite)+ O₂(g)→ CO₂(g)ΔH = -393.5 kJ The enthalpy of the reaction CaCO₃ (s)→ CaO (s)+ C (s,graphite)+ O₂ (g) Is ________ kJ. A)215.4 B)571.6 C)-215.4 D)-571.6 E)7.01 × 10⁴

Question

Quizplus · Accepted Answer

To determine the enthalpy of the given reaction, we need to manipulate the given reactions to obtain the desired equation. We can see that the first reaction is already in the right form, but the second reaction has to be reversed and multiplied by 2 to balance the carbon atoms: 2CO₂(g) → 2C (s,graphite) + 2O₂(g)ΔH = +787 kJ Now, we can add these two reactions together, cancelling out the CO₂(g) on both sides of the equation: CaCO₃ (s) + 2C (s,graphite) + 2O₂(g) → CaO (s) + 3CO₂ (g)ΔH = -178.1 kJ + 787 kJ Simplifying the equation gives: CaCO₃ (s) → CaO (s) + 3CO₂ (g)ΔH = 608.9 kJ Therefore, the enthalpy of the given reaction is 608.9 kJ, which corresponds to answer choice B.

Given the Following Reactions CaCO3 (S)→ CaO (S)+ CO2 (G)ΔH

Given the Following Reactions CaCO₃ (S)→ CaO (S)+ CO₂ (G)ΔH