An 6.11 g sample of calcium carbonate [CaCO₃ (s)] absorbs 84 J of heat, upon which the temperature of the sample increases from 19.2 °C to 35.9 °C. What is the specific heat of calcium carbonate?

Question

Quizplus · Accepted Answer

The specific heat (c) can be calculated using the formula q = mcΔT, where q is the heat absorbed (84 J), m is the mass (6.11 g), and ΔT is the temperature change (35.9 °C - 19.2 °C = 16.7 °C). Solving for c gives c = q / (mΔT) = 84 J / (6.11 g * 16.7 K) = 0.82 J/g-K.

An 611 G Sample of Calcium Carbonate [CaCO3 (S)] Absorbs 84

An 611 G Sample of Calcium Carbonate [CaCO₃ (S)] Absorbs 84