A 22.9 g sample of iron absorbs 155 J of heat, upon which the temperature of the sample increases from 23.9 °C to 38.9 °C. What is the specific heat of iron?

Question

Quizplus · Accepted Answer

The specific heat (c) can be calculated using the formula q = mcΔT, where q is the heat absorbed (155 J), m is the mass (22.9 g), and ΔT is the change in temperature (38.9 °C - 23.9 °C = 15.0 °C). Solving for c gives c = q / (mΔT) = 155 J / (22.9 g * 15.0 °C) = 0.451 J/g-K.

A 229 G Sample of Iron Absorbs 155 J of Heat