The de Broglie wavelength of a 0.02900 gram bullet traveling at the speed of 647.4 m/s is ________ m.

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The de Broglie wavelength is calculated using the formula λ = h / (mv), where h is Planck's constant (6.626 × 10^-34 m^2 kg/s), m is the mass in kg (0.02900 g = 0.000029 kg), and v is the velocity (647.4 m/s). Substituting these values gives λ = 6.626 × 10^-34 / (0.000029 × 647.4) = 3.529 × 10^-32 m.

The De Broglie Wavelength of a 0