The bond length in an HI molecule is 1.61 Å and the measured dipole moment is 0.44 D. What is the magnitude (in units of e)of the negative charge on I in HI? (1 debye = 3.34 × 10^-30 coulomb-meters; e = 1.6 × 10^-19 coulombs) A)1.6 × 10^-19 B)0.057 C)9.1 D)1 E)0.22

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The dipole moment (μ) is given by μ = q * d, where q is the charge and d is the bond length. Rearranging gives q = μ / d. Converting the dipole moment to coulomb-meters and bond length to meters, q = (0.44 D * 3.34 × 10^-30 C·m/D) / (1.61 × 10^-10 m) = 0.057 e.

The Bond Length in an HI Molecule Is 1