A vessel contains a mixture of 34.9 grams of H₂ (g)and 17.7 grams of CH₄. If the total pressure inside the vessel is measured at 2.92 atm, the partial pressure of H₂ (g)must be _____ atm. A)2.75 B)50.5 C)0.175 D)53.8 E)5.53

Question

Quizplus · Accepted Answer

The partial pressure of a gas in a mixture is proportional to its mole fraction. First, calculate the moles of each gas: H₂ = 34.9 g / 2.02 g/mol = 17.27 mol, CH₄ = 17.7 g / 16.04 g/mol = 1.10 mol. Total moles = 17.27 + 1.10 = 18.37 mol. Mole fraction of H₂ = 17.27 / 18.37 = 0.940. Partial pressure of H₂ = 0.940 * 2.92 atm = 2.75 atm.

A Vessel Contains a Mixture of 34