The Henry's law constant for helium gas in water at 30 °C is 3.70 × 10^-4 M/atm. When the partial pressure of helium above a sample of water is 0.400 atm, the concentration of helium in the water is ________ M. A)9.25 × 10^-4 B)1.08 × 10³ C)0.800 D)1.48 × 10^-4 E)3.70 × 10^-4

Question

Quizplus · Accepted Answer

Henry's law states that the concentration of a gas in a liquid is directly proportional to the partial pressure of that gas above the liquid.

Using Henry's law:

C = kH * P

where C is the concentration of the gas in the liquid, P is the partial pressure of the gas above the liquid, and kH is Henry's law constant.

Substituting the given values:

C = (3.70 × 10^-4 M/atm) * (0.400 atm) = 1.48 × 10^-4 M

Therefore, the concentration of helium in the water is 1.48 × 10^-4 M, which corresponds to choice D.

The Henry's Law Constant for Helium Gas in Water at 30