The rate constant for a particular second-order reaction is 0.47 M^-1s^-1. If the initial concentration of reactant is 0.25 mol/L, it takes ________ s for the concentration to decrease to 0.20 mol/L.

Question

Quizplus · Accepted Answer

For a second-order reaction, the integrated rate law is 1/[A] = kt + 1/[A]₀. Plugging in the values: 1/0.20 = 0.47 * t + 1/0.25, solving for t gives approximately 2.1 seconds.

The Rate Constant for a Particular Second-Order Reaction Is 0