The K_eq for the equilibrium below is 7.52 × 10^-2 at 480.0 °C. 2Cl₂ (g) + 2H₂O (g) 4HCl (g) + O₂ (g)
What is the value of K_eq at this temperature for the following reaction?
8HCl (g) + 2O₂ (g) 4Cl₂ (g) + 4H₂O (g)

Question

The K_eq for the equilibrium below is 7.52 × 10^-2 at 480.0 °C. 2Cl₂ (g) + 2H₂O (g)

The K<sub>eq</sub> for the equilibrium below is 7.52 × 10<sup>-2</sup> at 480.0 °C. 2Cl<sub>2</sub> (g) + 2H<sub>2</sub>O (g) 4HCl (g) + O<sub>2</sub> (g) What is the value of K<sub>eq</sub> at this temperature for the following reaction? 8HCl (g) + 2O<sub>2</sub> (g) 4Cl<sub>2</sub> (g) + 4H<sub>2</sub>O (g) A) 1.77 × 10<sup>2</sup> B) 5.66 × 10<sup>-3</sup> C) 1.50 × 10<sup>-1</sup> D) -7.52 × 10<sup>-2</sup> E) 7.52 × 10<sup>-2</sup>

4HCl (g) + O₂ (g)
What is the value of K_eq at this temperature for the following reaction?
8HCl (g) + 2O₂ (g)

4Cl₂ (g) + 4H₂O (g)

Quizplus · Accepted Answer

The Answer of The K_eq for the equilibrium below is 7.52 × 10^-2 at 480.0 °C. 2Cl₂ (g) + 2H₂O (g) 4HCl (g) + O₂ (g) What is the value of K_eq at this temperature for the following reaction? 8HCl (g) + 2O₂ (g) 4Cl₂ (g) + 4H₂O (g)

The Keq for the Equilibrium Below Is 7

The K_eq for the Equilibrium Below Is 7