Nitrosyl bromide decomposes according to the following equation. 2NOBr (g) 2NO (g) + Br₂ (g)
A sample of NOBr (0.64 mol) was placed in a 1.00-L flask containing no NO or Br₂. At equilibrium the flask contained 0.16 mol of NOBr. How many moles of NO and Br₂, respectively, are in the flask at equilibrium?

Question

Nitrosyl bromide decomposes according to the following equation. 2NOBr (g)

2NO (g) + Br₂ (g)
A sample of NOBr (0.64 mol) was placed in a 1.00-L flask containing no NO or Br₂. At equilibrium the flask contained 0.16 mol of NOBr. How many moles of NO and Br₂, respectively, are in the flask at equilibrium?

Quizplus · Accepted Answer

According to the balanced equation, 2 moles of NOBr give 2 moles of NO and 1 mole of Br2 at equilibrium.

Let x be the moles of NO that form at equilibrium, then the number of moles of Br2 would be x/2 since the ratio of moles of NO to Br2 is 2:1.

Using the law of conservation of mass, we can write:

Initial moles of NOBr = moles of NOBr at equilibrium + moles of NO at equilibrium + moles of Br2 at equilibrium

0.64 = 0.16 + x + (x/2)

Simplifying, we get:

0.64 = 1.5x + 0.16

1.5x = 0.48

x = 0.32

Therefore, the number of moles of NO at equilibrium is 0.32, and the number of moles of Br2 at equilibrium is 0.32/2 = 0.16.

So the answer is A) 0.48, 0.24.

Nitrosyl Bromide Decomposes According to the Following Equation