The K_sp for Zn(OH)₂ is 5.0 × 10^-17. Determine the molar solubility of Zn(OH)₂ in a buffer solution with a pH of 11.5.

Question

Quizplus · Accepted Answer

The molar solubility of Zn(OH)2 can be calculated using the following equation:

Ksp = [Zn2+][OH-]^2

Since the pH of the buffer solution is 11.5, we can assume that [OH-] = 10^-3.5 M (from the equation pH + pOH = 14).

Substituting into the Ksp equation gives:

5.0 × 10^-17 = [Zn2+](10^-3.5)^2

Solving for [Zn2+] gives:

[Zn2+] = 5.0 × 10^-12 M

Therefore, the molar solubility of Zn(OH)2 in the buffer solution with a pH of 11.5 is 5.0 × 10^-12 M. The correct answer is D.

The Ksp for Zn(OH)2 Is 5