The standard cell potential (E° cell)for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when [ Zn²⁺] = 3.0 M and [Pb²⁺] = 2.0 × 10^-4 M. Pb²⁺ (aq) + Zn (s) → Zn²⁺ (aq) + Pb (s) A)0.51 B)0.86 C)0.40 D)0.75 E)0.63

Question

Quizplus · Accepted Answer

The Nernst equation is used to calculate the cell potential under non-standard conditions: E = E° - (RT/nF) * ln(Q). Here, E° = 0.63 V, n = 2, Q = [Zn²⁺]/[Pb²⁺] = 3.0/(2.0 × 10⁻⁴). Plugging in the values and solving gives E ≈ 0.51 V.

The Standard Cell Potential (E° Cell)for the Reaction Below Is