The mass of a proton is 1.00728 amu and that of a neutron is 1.00867 amu. What is the binding energy (in J)of a ⁶²Co nucleus? (The mass of a cobalt-62 nucleus is 61.9341 amu.)

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The correct answer is A.The binding energy of a nucleus is the energy required to separate all the nucleons in the nucleus. The binding energy per nucleon is the binding energy divided by the number of nucleons in the nucleus. The binding energy per nucleon is a measure of the stability of the nucleus. The more stable the nucleus, the higher the binding energy per nucleon.The binding energy of a nucleus can be calculated using the following formula:```BE = (Zm_p + Nm_n - M_nucleus)c^2```where:* BE is the binding energy in joules* Z is the atomic number of the nucleus* m_p is the mass of a proton in kilograms* N is the number of neutrons in the nucleus* m_n is the mass of a neutron in kilograms* M_nucleus is the mass of the nucleus in kilograms* c is the speed of light in meters per secondThe mass of a proton is 1.00728 amu and the mass of a neutron is 1.00867 amu. The mass of a cobalt-62 nucleus is 61.9341 amu. The atomic number of cobalt is 27, so the number of protons in the nucleus is 27. The number of neutrons in the nucleus is 62 - 27 = 35.The binding energy of a cobalt-62 nucleus is:```BE = (27 * 1.00728 amu + 35 * 1.00867 amu - 61.9341 amu) * (1.66054 × 10^-27 kg/amu) * (299792458 m/s)^2``````BE = 8.46 × 10^-11 J```Therefore, the binding energy of a cobalt-62 nucleus is 8.46 × 10^-11 J.

The Mass of a Proton Is 1