A sample of CH₄O with a mass of 32.0 g contains ________ molecules of CH₄O. A)5.32 × 10^-23 B)1.00 C)1.88 × 10²² D)6.02 × 10²³ E)32.0

Question

Quizplus · Accepted Answer

To calculate the number of molecules, we need to use Avogadro's number, which is 6.02 × 10^23 molecules/mol. First, we need to determine the number of moles of CH₄O in the sample. This is done by dividing the mass by the molar mass (which can be calculated by adding the atomic masses of all the elements in the compound). The molar mass comes out to be approximately 584 g/mol. Therefore, the number of moles of CH₄O in the sample is 32.0 g / 584 g/mol = 0.0548 mol. Now, to get the number of molecules, we multiply the number of moles by Avogadro's number: 0.0548 mol × 6.02 × 10^23 molecules/mol = 3.30 × 10^22 molecules. The answer closest to this value is D, which is 6.02 × 10^23.

A Sample of CH4O with a Mass of 32

A Sample of CH₄O with a Mass of 32