Lithium and nitrogen react to produce lithium nitride: 6Li (s) + N₂ (g) → 2Li₃N (s)
How many moles of N₂ are needed to react with 0.710 mol of lithium?

Question

Lithium and nitrogen react to produce lithium nitride: 6Li (s)+ N₂ (g)→ 2Li₃N (s) How many moles of N₂ are needed to react with 0.710 mol of lithium? A)4.26 B)0.710 C)0.237 D)2.13 E)0.118

Quizplus · Accepted Answer

According to the balanced equation, 6 moles of Li react with 1 mole of N₂. Therefore, 0.710 moles of Li would require 0.710/6 = 0.118 moles of N₂.

Lithium and Nitrogen React to Produce Lithium Nitride: 6Li (S)